Fast signed multiply: Difference between revisions
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The following code multiplies two 8-bit signed integers, of range (-64..+64). The output is a signed 16-bit result, in range (-4096..4096). It uses a 256 byte lokup table, but is quite fast. | The following code multiplies two 8-bit signed integers, of range (-64..+64). The output is a signed 16-bit result, in range (-4096..4096). It uses a 256 byte lokup table, but is quite fast. | ||
< | <source lang="6502tasm"> | ||
;Fast table driven signed multiply routine | ;Fast table driven signed multiply routine | ||
;It multiplies Y with A, and relies on the mathematical fact (a+b)^2-(a-b)^2 = 4*a*b | ;It multiplies Y with A, and relies on the mathematical fact (a+b)^2-(a-b)^2 = 4*a*b | ||
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.endr | .endr | ||
.ends | .ends | ||
</ | </source> |
Revision as of 09:04, 24 August 2013
The following code multiplies two 8-bit signed integers, of range (-64..+64). The output is a signed 16-bit result, in range (-4096..4096). It uses a 256 byte lokup table, but is quite fast.
<source lang="6502tasm">
- Fast table driven signed multiply routine
- It multiplies Y with A, and relies on the mathematical fact (a+b)^2-(a-b)^2 = 4*a*b
- Also both inputs and outputs are SIGNED and are never supposed to be outside of the range (-64; +64)
- Return with YA = 4*A*Y (result can be shifted as necessary)
Multiply
sty Temp
pha clc adc Temp ;Add two multiplicands together bpl + eor #$ff clc adc #$01 ;If result is negative, force it to be positive + asl A tax ;The square of a negative number is equal to its pos counterpart anyways
pla sec sbc Temp ;Compute difference of two multiplicands bpl + eor #$ff ;Again, force the result to be positive clc adc #$01 + asl A tay
lda SquareTbl,X sec sbc SquareTbl,Y ;Compute (a+y)^2-(a-y)^2 pha lda SquareTbl+1,X sbc SquareTbl+1,Y
tay pla
rts
- This is a square table for the multiply routine
- Note that this macro is for WLA-DX, but can be adapted
- For most assemblers
SquareTbl .def i = 0 .rept 128 .dw i^2 ;Create a square table with 128 word entries .redef i i+1 .endr .ends </source>